With them in series, the current through both resistors will be the same, call it I. The power disipation is (I^2)R
What exactly are you trying to do?
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::Hi,
:If I hook up a 100watt 3ohm resistor with a 10 watt 290ohm resistor in series, will the combination be able to dissipate 110 watts of heat or will the 10 watt resistor be a weak link? I'm trying to build something using parts from my junk box. That is why I ask. Info appreciated.
:Bob Masse
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Lets assume you want to run 1 amp thru the series combination. The 3 ohm resistor will dissipate 3 watts; the 290 ohm resistor will dissipate 290 watts. Heating is equal to: current (squared) x resistance. In a series string, the greater voltage (and hence, greater power) appears at the higher resistance element.
Rich
:
::
::Hi,
:If I hook up a 100watt 3ohm resistor with a 10 watt 290ohm resistor in series, will the combination be able to dissipate 110 watts of heat or will the 10 watt resistor be a weak link? I'm trying to build something using parts from my junk box. That is why I ask. Info appreciated.
:Bob Masse
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::
:
:
;:Bob,
:
:Lets assume you want to run 1 amp thru the series combination. The 3 ohm resistor will dissipate 3 watts; the 290 ohm resistor will dissipate 290 watts. Heating is equal to: current (squared) x resistance. In a series string, the greater voltage (and hence, greater power) appears at the higher resistance element.
:Rich
:
:
:
::
:::
:::Hi,
::If I hook up a 100watt 3ohm resistor with a 10 watt 290ohm resistor in series, will the combination be able to dissipate 110 watts of heat or will the 10 watt resistor be a weak link? I'm trying to build something using parts from my junk box. That is why I ask. Info appreciated.
::Bob Masse
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