My battery-powered TRF radio has six 01As, the output tube is operating at 130 volts. The DC resistance of the high impedance speaker I am using is about 1300 ohms. Is it a basic Ohm’s law calculation to determine how much current the output tube is drawing or does impedance factor into the calculation as well?

(Forgot to mention the voltage drop when determining calculation.)

:My battery-powered TRF radio has six 01As, the output tube is operating at 130 volts. The DC resistance of the high impedance speaker I am using is about 1300 ohms. Is it a basic Ohm’s law calculation to determine how much current the output tube is drawing or does impedance factor into the calculation as well?
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It should be 2-3 ma draw for an 01A depending on the grid bias. You can measure this with a dc ammeter.
Once you have the current, and know the difference between the supply voltage and the potential at the cathode (filament in this case,) You can use ohm's law to figure the exact resistance the circuit presents to the B+. E=I*R. And, of course the amount of power going into the output device is W=E*R.

Impedence is a whole other kettle of fish.

:(Forgot to mention the voltage drop when determining calculation.)
:
::My battery-powered TRF radio has six 01As, the output tube is operating at 130 volts. The DC resistance of the high impedance speaker I am using is about 1300 ohms. Is it a basic Ohm’s law calculation to determine how much current the output tube is drawing or does impedance factor into the calculation as well?
::
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Yes. Measure the resistance of the speaker. Then measure the voltages on either side of it. Divide the voltage drop by the resistance of the speaker. I=E/R

Impeadance comes into the picture when dealing with getting the proper load on the output tube for signal transfer. It does not affect the dc current.

:(Forgot to mention the voltage drop when determining calculation.)
:
::My battery-powered TRF radio has six 01As, the output tube is operating at 130 volts. The DC resistance of the high impedance speaker I am using is about 1300 ohms. Is it a basic Ohm’s law calculation to determine how much current the output tube is drawing or does impedance factor into the calculation as well?
::
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