I need help here with this 2 section resistor.
It is a Philco 112 (serial no above 174000)
Are A-B and B-C the separate 70 ohm sections of part 69 resistor?
From C to the Chassis ground boltloop thing...what is
missing here?
Part D looks to be a burnt and has 7 or so windings
visible. This is all that was in the set. I saw no pieces laying around.
My question is how to replace this No 69 the two part resistor.
and whatever that is that is burned?
The wire connected to A goes to the transformer
and the wire from B goes to Bakelite BlockCap part number 6 (By-pass condenser) via a hook up on the chassis.
When I measure between A-B and B-C I get roughly 140-150 ohms.
Do I need whatever D is (or was)?
thanks, Bob E.
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In tracking down those wires to their circuitry tie ins, using your descriptions, seems to confirm their circuitry locations, with cross referencing back to the schematic, and all does seems correct. Your photo seems to make it look like that MUTER power resistor strip is ACTUALLY a 3 section unit, which has a very crude jumper wire / buss between your C-D designations, thus effectively shunting out that section.
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:I need help here with this 2 section resistor.
:It is a Philco 112 (serial no above 174000)
:
:Are A-B and B-C the separate 70 ohm sections of part 69 resistor?
:
:From C to the Chassis ground boltloop thing...what is
:missing here?
:
:Part D looks to be a burnt and has 7 or so windings
:visible. This is all that was in the set. I saw no pieces laying around.
:
:My question is how to replace this No 69 the two part resistor.
:and whatever that is that is burned?
:The wire connected to A goes to the transformer
:and the wire from B goes to Bakelite BlockCap part number 6 (By-pass condenser) via a hook up on the chassis.
:When I measure between A-B and B-C I get roughly 140-150 ohms.
:Do I need whatever D is (or was)?
:thanks, Bob E.
:
http://www.philcorepairbench.com/flexrest.htm
This link will also show those bakelite block capacitors as well. You do need to replace those with modern day equivalent with the same values.
The part "D" is what's left of the original resistor.
:Being those were wire wound in the power supply, I would use two 70 ohm resistors of at least 5 watts in series to be on the safe side.
:
http://www.philcorepairbench.com/flexrest.htm
I see what the whole part of my burnt resistor probably looked like at the upper left of his resistor page. So now I am wondering if that other part which goes from A to C (my photo designations) was a replacement for the burned part? and therefore all I
need are two 70 ohm 5 watt to replace that A-D section?
...and the A to C piece is not needed correct?
(I just noticed that I did not pay very close attention to your first post about the Schwark page.. sorry.)
:Electronically your are simulating that old flex resistor with two new resistors in series. Where the new resistors are soldered together is your new B connection.
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...and the A to C piece is not needed correct?
(I just noticed that I did not pay very close attention to your first post about the Schwark page.. sorry.)
:Electronically your are simulating that old flex resistor with two new resistors in series. Where the new resistors are soldered together is your new B connection.
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