Referencing Rider's schematic {pages 12-57 and 12-58} obtained from this site I have the following questions:
1. Can someone with a more legible copy respond with the actual values for the five sections, a-e, and
2. also what size {wattage} resistors should I use? I'm thinking 10 watt for section "a", 5 watt for sections "b and c", and 2 watts for "d and e".
Any other comments or suggestions would be most welcome.
Thanks, Ed
:
:Referencing Rider's schematic {pages 12-57 and 12-58} obtained from this site I have the following questions:
:
:1. Can someone with a more legible copy respond with the actual values for the five sections, a-e, and
:
:2. also what size {wattage} resistors should I use? I'm thinking 10 watt for section "a", 5 watt for sections "b and c", and 2 watts for "d and e".
:
:Any other comments or suggestions would be most welcome.
:
:Thanks, Ed
A quick calculation verifies your thinking is good re wattage.
Here is the component value chart from the schematic.
http://home.comcast.net/~suptjud/GEFE112.JPG
MMMmmmmm...now, thats one full house receiver, Ree-splendently complete with an RF front end amp stage and EVEN utilizing dual IF's no less !
I used the best "clarified" copy that I could find and ran it thru two digital enhancement techniques BUT there is just so much that can be done with an original document that was the created product of some olden DRAFTSMAN and utilizing his hand "lettering" entry's. At least, more "modern" typesetting of that time frame would have created a uniform repetition of a font, for later comparison against. The original might have even been a shared document, passed around between different peoples (and their distinct lettering styles) for different entry's and proofing !
I created an even more "enhanced" version of the point of interest on the link supplied below. The A+B+C resistive values are across the full 315 VDC supply and its division.... along with the shunted circuitry...figures at ~ 5 watts so cool running 10 watt WW units should take care of the problem from now on.
The HV transformer secondary center tap passes thru section D and E to derive the negative bias voltage needs, with them being minimal, but the whole B+ return current of ~ 100 ma max could passing thru that string at certain taxing times. That being in the order of ~1.5 watts dissipation, but a 3 or 5 watt unit should definitely be trouble free and cool.
The locating of those precise values in wire wounds would be hard to come by, plus... this is not a rocket science application, so the typical 10% tolerance would be in order.The first level of dropped voltage is for part of the AF circuitry and the front end RF circuitry with the local osc B+ being the most critical supply of those.
Also, those read out values were typically on a service grade ohmmeter or bridge and not too accurate at those times.
The closest approximation of values could be acquired by the use of the nearest resistive value just above the desired value and shunting across a resistive value with a much higher value of 1-2 watt modern metal film resistor ,where just about any value needed is available, the shunted pair then produces the desired final value. With the added shunting resistor being of a proportionately higher ratio of resistance, the shared current / power division is proportionately divided between the two units, such that the small unit may only see 1/4-1/2 watt across it while the main WW unit is dissipating the majority. The end result, with you then having the combined resistance value trimmed down to the specified resistance desired.
Approximation of Values:
For the 1600 ohm unit, the power resistor could be a stock 2K pwr WW unit shunted with a 10K metal film unit to yield ~ 1667 ohms.
For the 11,000 ohm unit, a 20k unit shunted with a 22k unit would yield ~ 10476 ohms, where both would be sharing about half of the current / wattage. This being the sole worst case in all of the combinations to be mentioned. Unless a rarer, 15 K power unit could be found for the base unit value. That with a 39K shunt gives a final~ 10,833 ohms with less wattage dissipation being across the film unit.
For the 8,900 ohm unit, a 10K power unit shunted with a 82K film unit would yield 8913 ohms.
For the 27 ohm value..... that is a common stock value.
For the final 85 ohm value,that could be had with a 100 ohm power unit shunted with a 560 ohm film unit to acquire ~84.8 ohms.
I am tacking on that new schema parts thumbnail copy below.....any one call out if further revisions / corrections seem to be needed.....MAG it on up....as its J-pegged.
73's de Edd
::I'm currently working on a GE FE-112 and have decided to replace completely the original candohm.
::
::Referencing Rider's schematic {pages 12-57 and 12-58} obtained from this site I have the following questions:
::
::1. Can someone with a more legible copy respond with the actual values for the five sections, a-e, and
::
::2. also what size {wattage} resistors should I use? I'm thinking 10 watt for section "a", 5 watt for sections "b and c", and 2 watts for "d and e".
::
::Any other comments or suggestions would be most welcome.
::
::Thanks, Ed
:
:A quick calculation verifies your thinking is good re wattage.
:Here is the component value chart from the schematic.
:http://home.comcast.net/~suptjud/GEFE112.JPG
Just finished labeling all attached wires and components and performed the candohm-ectomy.
Have to install solder terminals and gather up the necessary resistors. Hadn't thought about paralleling resistors but I like the idea. Thanks, Edd.
There's a lot of work to be done on this set--numerous paper caps, electrolytics, deteriorating rubber wire, and some earlier repairs that left large gobs of solder on connections and many flying splices. I'm consuming solder terminals at an alarming pace LOL.
Will update as progress continues. This will challenge me and I'll certainly have many more questions.
Thanks again, ED
:
:
:
:
:
:
:
:MMMmmmmm...now, thats one full house receiver, Ree-splendently complete with an RF front end amp stage and EVEN utilizing dual IF's no less !
:
:I used the best "clarified" copy that I could find and ran it thru two digital enhancement techniques BUT there is just so much that can be done with an original document that was the created product of some olden DRAFTSMAN and utilizing his hand "lettering" entry's. At least, more "modern" typesetting of that time frame would have created a uniform repetition of a font, for later comparison against. The original might have even been a shared document, passed around between different peoples (and their distinct lettering styles) for different entry's and proofing !
:
:
:I created an even more "enhanced" version of the point of interest on the link supplied below. The A+B+C resistive values are across the full 315 VDC supply and its division.... along with the shunted circuitry...figures at ~ 5 watts so cool running 10 watt WW units should take care of the problem from now on.
:
:
:The HV transformer secondary center tap passes thru section D and E to derive the negative bias voltage needs, with them being minimal, but the whole B+ return current of ~ 100 ma max could passing thru that string at certain taxing times. That being in the order of ~1.5 watts dissipation, but a 3 or 5 watt unit should definitely be trouble free and cool.
:
:
:The locating of those precise values in wire wounds would be hard to come by, plus... this is not a rocket science application, so the typical 10% tolerance would be in order.The first level of dropped voltage is for part of the AF circuitry and the front end RF circuitry with the local osc B+ being the most critical supply of those.
:
:
:Also, those read out values were typically on a service grade ohmmeter or bridge and not too accurate at those times.
:
:The closest approximation of values could be acquired by the use of the nearest resistive value just above the desired value and shunting across a resistive value with a much higher value of 1-2 watt modern metal film resistor ,where just about any value needed is available, the shunted pair then produces the desired final value. With the added shunting resistor being of a proportionately higher ratio of resistance, the shared current / power division is proportionately divided between the two units, such that the small unit may only see 1/4-1/2 watt across it while the main WW unit is dissipating the majority. The end result, with you then having the combined resistance value trimmed down to the specified resistance desired.
:
:
:Approximation of Values:
:
:For the 1600 ohm unit, the power resistor could be a stock 2K pwr WW unit shunted with a 10K metal film unit to yield ~ 1667 ohms.
:
:For the 11,000 ohm unit, a 20k unit shunted with a 22k unit would yield ~ 10476 ohms, where both would be sharing about half of the current / wattage. This being the sole worst case in all of the combinations to be mentioned. Unless a rarer, 15 K power unit could be found for the base unit value. That with a 39K shunt gives a final~ 10,833 ohms with less wattage dissipation being across the film unit.
:
:For the 8,900 ohm unit, a 10K power unit shunted with a 82K film unit would yield 8913 ohms.
:
:For the 27 ohm value..... that is a common stock value.
:
:For the final 85 ohm value,that could be had with a 100 ohm power unit shunted with a 560 ohm film unit to acquire ~84.8 ohms.
:
:
:I am tacking on that new schema parts thumbnail copy below.....any one call out if further revisions / corrections seem to be needed.....MAG it on up....as its J-pegged.
:
:
:
:
:
:
:
:73's de Edd
:
:
:
:
:
:
:
:
:::I'm currently working on a GE FE-112 and have decided to replace completely the original candohm.
:::
:::Referencing Rider's schematic {pages 12-57 and 12-58} obtained from this site I have the following questions:
:::
:::1. Can someone with a more legible copy respond with the actual values for the five sections, a-e, and
:::
:::2. also what size {wattage} resistors should I use? I'm thinking 10 watt for section "a", 5 watt for sections "b and c", and 2 watts for "d and e".
:::
:::Any other comments or suggestions would be most welcome.
:::
:::Thanks, Ed
::
::A quick calculation verifies your thinking is good re wattage.
::Here is the component value chart from the schematic.
::http://home.comcast.net/~suptjud/GEFE112.JPG
It was touch and go for a while. The radio would lose audio intermittantly even though all tubes tested good on my tube tester. By checking voltages I found there was no voltage at C73 which, if I understand the schematic, is derived from the cathode of the 6F5. So I replaced the 6F5 and so far so good.
Also the band switch has a very tiny "sweet spot" for the broadcast band and is a little touchy.
Thanks again and have a HAPPY THANKSGIVING!!
::Thanks guys, both Terry and Edd!! You certainly went the extra mile in helping me out and I really appreciate it.
:
:Just finished labeling all attached wires and components and performed the candohm-ectomy.
:
:Have to install solder terminals and gather up the necessary resistors. Hadn't thought about paralleling resistors but I like the idea. Thanks, Edd.
:
:There's a lot of work to be done on this set--numerous paper caps, electrolytics, deteriorating rubber wire, and some earlier repairs that left large gobs of solder on connections and many flying splices. I'm consuming solder terminals at an alarming pace LOL.
:
:Will update as progress continues. This will challenge me and I'll certainly have many more questions.
:
:Thanks again, ED
::
::
::
::
::
::
::
::MMMmmmmm...now, thats one full house receiver, Ree-splendently complete with an RF front end amp stage and EVEN utilizing dual IF's no less !
::
::I used the best "clarified" copy that I could find and ran it thru two digital enhancement techniques BUT there is just so much that can be done with an original document that was the created product of some olden DRAFTSMAN and utilizing his hand "lettering" entry's. At least, more "modern" typesetting of that time frame would have created a uniform repetition of a font, for later comparison against. The original might have even been a shared document, passed around between different peoples (and their distinct lettering styles) for different entry's and proofing !
::
::
::I created an even more "enhanced" version of the point of interest on the link supplied below. The A+B+C resistive values are across the full 315 VDC supply and its division.... along with the shunted circuitry...figures at ~ 5 watts so cool running 10 watt WW units should take care of the problem from now on.
::
::
::The HV transformer secondary center tap passes thru section D and E to derive the negative bias voltage needs, with them being minimal, but the whole B+ return current of ~ 100 ma max could passing thru that string at certain taxing times. That being in the order of ~1.5 watts dissipation, but a 3 or 5 watt unit should definitely be trouble free and cool.
::
::
::The locating of those precise values in wire wounds would be hard to come by, plus... this is not a rocket science application, so the typical 10% tolerance would be in order.The first level of dropped voltage is for part of the AF circuitry and the front end RF circuitry with the local osc B+ being the most critical supply of those.
::
::
::Also, those read out values were typically on a service grade ohmmeter or bridge and not too accurate at those times.
::
::The closest approximation of values could be acquired by the use of the nearest resistive value just above the desired value and shunting across a resistive value with a much higher value of 1-2 watt modern metal film resistor ,where just about any value needed is available, the shunted pair then produces the desired final value. With the added shunting resistor being of a proportionately higher ratio of resistance, the shared current / power division is proportionately divided between the two units, such that the small unit may only see 1/4-1/2 watt across it while the main WW unit is dissipating the majority. The end result, with you then having the combined resistance value trimmed down to the specified resistance desired.
::
::
::Approximation of Values:
::
::For the 1600 ohm unit, the power resistor could be a stock 2K pwr WW unit shunted with a 10K metal film unit to yield ~ 1667 ohms.
::
::For the 11,000 ohm unit, a 20k unit shunted with a 22k unit would yield ~ 10476 ohms, where both would be sharing about half of the current / wattage. This being the sole worst case in all of the combinations to be mentioned. Unless a rarer, 15 K power unit could be found for the base unit value. That with a 39K shunt gives a final~ 10,833 ohms with less wattage dissipation being across the film unit.
::
::For the 8,900 ohm unit, a 10K power unit shunted with a 82K film unit would yield 8913 ohms.
::
::For the 27 ohm value..... that is a common stock value.
::
::For the final 85 ohm value,that could be had with a 100 ohm power unit shunted with a 560 ohm film unit to acquire ~84.8 ohms.
::
::
::I am tacking on that new schema parts thumbnail copy below.....any one call out if further revisions / corrections seem to be needed.....MAG it on up....as its J-pegged.
::
::
::
::
::
::
::
::73's de Edd
::
::
::
::
::
::
::
::
::::I'm currently working on a GE FE-112 and have decided to replace completely the original candohm.
::::
::::Referencing Rider's schematic {pages 12-57 and 12-58} obtained from this site I have the following questions:
::::
::::1. Can someone with a more legible copy respond with the actual values for the five sections, a-e, and
::::
::::2. also what size {wattage} resistors should I use? I'm thinking 10 watt for section "a", 5 watt for sections "b and c", and 2 watts for "d and e".
::::
::::Any other comments or suggestions would be most welcome.
::::
::::Thanks, Ed
:::
:::A quick calculation verifies your thinking is good re wattage.
:::Here is the component value chart from the schematic.
:::http://home.comcast.net/~suptjud/GEFE112.JPG
You are a tireless indispensable GEM!
:
:You are a tireless indispensable GEM!
Yep.