I decided not to restuff the can and to hang replacements under the chassis, leaving the can in place for ornamentation. So, I cut the negative B- terminal from the can, and haywired the replacement caps from the respective positive terminals. I didn't cut the four positive terminals from the can, figuring that with the old negative terminals cut, the old caps would do no harm. I've done this in the past with no problem.
With the replacement filter caps, the set had a bad hum, which resisted troubleshooting. I decided to try cutting the positive terminals to the old can, and the hum disappeared.
Problem solved, but I can't figure out why leaving the positive terminals energized caused the hum. Any thoughts?
I think that it may have just acted like it tied the 2 sections togather. Putting new caps in paralel with the old ones, i think to leak from cap tp cap, was bypassing the new caps, it was the path of least rsistance. It was easier to bypass the new caps, and tale the high resistance path to the ground. I hope that may make some sense.
marv
:Thanks, JK, that's a possibility. But if there were such a short, wouldn't it have caused a problem before I replaced the filter caps?
I think JK nailed it. With four different e-caps in the can, all the negative leads were tied together by the can itself. Each positive terminal was at a different voltage (e.g., one at 90V B+ and one at 10V A voltage). So there were all kinds of cross-ties and backfeeds between the positive terminals thru the old caps.
I'm now wondering how I got by with this in the past. The thing that makes a Zenith TransOceanic a little different is the filament circuit. Unlike a normal AC/DC set, the tube's filaments are not connected across the AC line. Instead, the filament feed (about 9V) is derived from the B+ through a voltage-drop resistor. The voltage differential across the e-cap on the filament circuit and the other e-caps is very large.
I think just cutting the positive terminals is OK, but I realize that it would be frowned upon by those who would restuff the old can.
No radiation is taking place. There´s no AC voltage to radiate.
Thomas
:Nice try everyone, but that´s not it. Here´s the simple reason. Original caps were bad and probably had leakage. They´re all tied together by the can. Any filtering provided by the various resistors within the set is reduced since current is allowed to leak past the resistors through these leaky electrolytics. Current will leak through one leaky condenser, through the can, and then through another leaky condenser, into another circuit, placing incorrect voltages all over the place, and voiding any filtering created by various filtering resistors. These cans often have the filament wiring and cathode wiring and B wiring all being filtered from one can. Leakage can throw incorrect voltages all over the place, especially into the filament wiring. Also, with leaks going from B+ to the cathode and filament wiring (which is at the low end of the B chain), there will be excessive loading of the power supply, which will cause hum. Even if serious loading isn´t taking place, any shortcut around filtering to the filaments will cause serious hum due to the nature of these filaments.
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:No radiation is taking place. There´s no AC voltage to radiate.
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:Thomas
Thomas
Some of you may have already experienced this when rebuilding the early "tuned" filters in which very low value condensers were used, and a very low value (say .1 MFD) condenser was bridged across the field coil or choke. Originally this condenser worked in resonance with the choke or coil to buffer out hum. Replacing other condensers with much higher values threw off tuning of the supply, and replacing this condenser with a higher value certainly threw off tuning of the coil, creating more hum than if the condenser wasn´t there at all.
Thomas
The electrolytics in a radio set are charged up every time current flows through the rectifier. Every time current doesn´t flow through the rectifier, current is taken from the electrolytics. The electrolytics fill in the gaps. In most filter circuits, there will be an electrolytic across from the + to - of the circuit. Resistors or chokes will be placed in the circuit to aid in filtering. To simplify the explanation, let´s say that a resistor is placed between the rectifier and the rest of the radio--on the positive side of the circuit. Another electrolytic will be placed after this resistor from the resistor to the negative side of the circuit. The resistor will slow the current draw from the first electrolytic, and the second electrolytic will smooth out any ripple that the first one didn´t. The power supply is set up so that the voltage at the first electrolytic is going to be more than the radio needs. Placing a resistor in series with this point and the rest of the radio reduces the current to the appropriate level for the radio, and, at the same time, allows the electrolytic to charge up a bit more. If a choke were used, it would have one more asset. Magnetic fields that build up and break down within the choke due to voltage ripple, create an effect similar to moving magnets on a generator. These build ups and break downs of magnetic fields generate or induce additional currents within the coil which give the current inertia, and make it want to keep flowing whenever it is at a low, and make it slow down just a bit when it wants to speed up...this further aids in smoothing out ripples in the current. Still, none of the ripples are due to alternating current--current that flows back and forth. They are only due to current that is building up and breaking down in intensity--never changing direction.
Regarding the original radio problem for this thread, the original electrolytics were connected to various points within the B+ circuit, with all of their negatives tied together. This common negative was then connected to the negative side of the B circuit. To simplify things, let´s stick to the one resistor circuit described above. We have an electrolytic prior to this resistor from + to -, and we have an electrolytic after the resistor, on the radio side of the resistor, going from + to -. Both condensers common at the same - point. Now, let´s say that we chop their negative leads from the negative power supply wire, but leave the leads connected together. (We of course put in new electrolytics wired as the old ones were initially wired). The old electrolytics, tied together at their commons, effectively form a condenser across the filter resistor. Condensers are said to pass alternating currents. They can also pass pulsating direct currents provided that they have a way of discharging between pulses. In amplifiers this discharge route is provided by the grid biasing resistor, which leaks off voltage through the B circuit. In the case of our circuit above, the filter resistor forms the leak for the condenser which is connected across it (two condensers wired in series, joined at their commons). Normally the filter resistor would dampen the voltage drawn off of the first electrolytic and off of the rectifier. However, there is a condenser connected across this resistor, which will easily pass a pulse of current. Now, you´d think that since this is direct current, after the pulse went through the condenser once, it´d be charged up, and the condenser wouldn´t pass anymore pulses. However, it is in parallel with a resistor. The resistor will discharge the condenser in between pulses, making it ready for each next pulse. In this way the condenser will pass the full jolt of each DC ripple from the rectifier.
Thomas
to,
too,
two
:
I get all mixed up if you use too when you mean to.
Please help me... ...lol
just kidding but sincere...lol