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In need of RCA Victor power xfmr for 9T or 9K2 chassis
3/6/2006 8:00:51 PMPaul - WA6EUZ
Being the Ham with the tall tower in the neighborhood gets me requests to fix anything fron toasters to radio controlled cars. My latest venture is to try and repair an old RCA radio (vintage 1936). I am looking for a power xfmr for an RCA 9T or 9K2 chassis and dont have a clue where to start! Are there any web sites where these types of items might be found for old radio restoration?

Thanks Paul - WA6EUZ

3/6/2006 8:18:24 PMJon
:Being the Ham with the tall tower in the neighborhood gets me requests to fix anything fron toasters to radio controlled cars. My latest venture is to try and repair an old RCA radio (vintage 1936). I am looking for a power xfmr for an RCA 9T or 9K2 chassis and dont have a clue where to start! Are there any web sites where these types of items might be found for old radio restoration?
:
:Thanks Paul - WA6EUZ

Paul,
Try www.oldradioparts.com. They carry millions of original radio parts. Pull up the schematic on this site to determine the voltage needs. For modern replacements try Antique Electronic Supply at www.tubesandmore.com. Good luck
Jon
:

3/7/2006 4:09:58 AMPaul

:
:Paul,
: Try www.oldradioparts.com. They carry millions of original radio parts. Pull up the schematic on this site to determine the voltage needs. For modern replacements try Antique Electronic Supply at www.tubesandmore.com. Good luck
:Jon
::

Jon:

Thanks...will check them out.

Paul

3/7/2006 10:57:05 AMThomas Dermody
Be sure that if you order a modern replacement, you get the current ratings correct. This radio looks like it'll draw a lot of filament and B current. If you don't know what the B current should be but know what its voltage should be, you can take all of the 6.3 volt tubes' amperages and add them together. Then divide the amperage by the voltage. This will give you the wattage. Do the same for the rectifier (5.0 volts). Then subtract this wattage from the receiver's total wattage. This will give you the remaining wattage for the B supply plus some extra wattage consumed by the inefficiency of the transformer. Do reverse math if you know the voltage of the B supply's winding (each half, not the whole thing).

Thomas



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